Answer: OPTION C
Step-by-step explanation:
Complete the square:
Having the equation in the form [tex]ax^2+bx=c[/tex], you need to add [tex](\frac{b}{2})^2[/tex] to both sides of the equation:
You can identify that "b" in the equation [tex]x^2+6x=5[/tex] is:
[tex]b=6[/tex]
Then:
[tex](\frac{6}{2})^2=3^2[/tex]
Add this to both sides:
[tex]x^2+6x+3^2=5+3^2[/tex]
Rewriting, you get:
[tex](x+3)^2=14[/tex]
Solve for "x":
[tex]x+3=\±\sqrt{14}\\\\x+3=\±\sqrt{14}\\\\x=\±\sqrt{14}-3[/tex]
Then, the solutions are:
[tex]x=-3+\sqrt{14}\ or\ x=-3-\sqrt{14}[/tex]
