Which of the following are equations for the line shown below? Check all that
apply
(-1,5)
O
A. y-2 = -0.75(x-3)
B. y-5 = -0.75(x-1)
C. y-3 = -0.75(x - 2)
D. y-5-0.75(x+1)

Which of the following are equations for the line shown below Check all that apply 15 O A y2 075x3 B y5 075x1 C y3 075x 2 D y5075x1 class=

Respuesta :

Hello!

The answer is:

The correct options are:

A)  [tex]y-2=-0.75(x-3)[/tex]

and

D) [tex]y-5=-0.75(x+1)[/tex]

Why?

To find the correct answers, we need to find a equation that meet the following charactheristics:

From the graph we can se that the function:

- Has a negative slope (is decreasing)

- Pass throught the points: (-1,5) and (3,2)

Now, discarding from the given options, we have:

A.  

[tex]y-2=-0.75(x-3)[/tex]

We have that the coefficient of the linear term is negative (-0.75), so, the slope is negative (the function is decreasing).

Evaluating the points, we have:

Evaluating (-1,5)

[tex]5-2=-0.75(-1-3)[/tex]

[tex]3=-0.75(-4)[/tex]

[tex]3=3[/tex]

Evaluating (3,2):

[tex]2-2=-0.75(3-3)[/tex]

[tex]0=-0.75(0)[/tex]

[tex]0=0[/tex]

We have that the equation is satisfied, so,  the line pass  through the given points.

Hence, we have that the equation A is an equation of the line shown.

B.

[tex]y-5=-0.75(x-1)[/tex]

We have that the coefficient of the linear term is negative (-0.75), so, the slope is negative (the function is decreasing).

Evaluating the points, we have:

Evaluating (-1,5)

[tex]5-5=-0.75(-1-1)[/tex]

[tex]0=-3.5[/tex]

Hence, we have that since the equation is not satisfied, the line shown is not passing  through the point (-1,5) meaning that the equation is not an equation of the line shown.

So,  we have that the equation B is not equation of the line shown.

C.

[tex]y-3=-0.75(x-2)[/tex]

We have that the coefficient of the linear term is negative (-0.75), so, the slope is negative (the function is decreasing).

Evaluating the points, we have:

Evaluating (-1,5)

[tex]5-3=-0.75(-1-2)[/tex]

[tex]2=-0.75(-3)[/tex]

[tex]2=2.25[/tex]

Hence, we have that since the equation is not satisfied, the line shown is not passing  through the point (-1,5) meaning that the equation is not an equation of the line shown.

So, we have that the equation B is not equation of the line shown.

D.

(assuming you committed a mistake writing the options and the equality sign is missing)

[tex]y-5=-0.75(x+1)[/tex]

We have that the coefficient of the linear term is negative (-0.75), so, the slope is negative (the function is decreasing).

Evaluating the points, we have:

Evaluating (-1,5)

[tex]5-5=-0.75(-1+1)[/tex]

[tex]0=-0.75(0)[/tex]

[tex]0=0[/tex]

Evaluating (3,2)

[tex]2-5=-0.75(3+1)[/tex]

[tex]-3=-0.75(4)[/tex]

[tex]-3=-3[/tex]

We have that the equation is satisfied, so,  the line pass  through the given points.

Hence, we have that the equation B is an equation of the line shown.

Finally, we have that the correct options are:

A)  [tex]y-2=-0.75(x-3)[/tex]

and

D) [tex]y-5=-0.75(x+1)[/tex]

Have a nice day!

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