Hello!
The answer is:
The correct options are:
A) [tex]y-2=-0.75(x-3)[/tex]
and
D) [tex]y-5=-0.75(x+1)[/tex]
Why?
To find the correct answers, we need to find a equation that meet the following charactheristics:
From the graph we can se that the function:
- Has a negative slope (is decreasing)
- Pass throught the points: (-1,5) and (3,2)
Now, discarding from the given options, we have:
A.
[tex]y-2=-0.75(x-3)[/tex]
We have that the coefficient of the linear term is negative (-0.75), so, the slope is negative (the function is decreasing).
Evaluating the points, we have:
Evaluating (-1,5)
[tex]5-2=-0.75(-1-3)[/tex]
[tex]3=-0.75(-4)[/tex]
[tex]3=3[/tex]
Evaluating (3,2):
[tex]2-2=-0.75(3-3)[/tex]
[tex]0=-0.75(0)[/tex]
[tex]0=0[/tex]
We have that the equation is satisfied, so, the line pass through the given points.
Hence, we have that the equation A is an equation of the line shown.
B.
[tex]y-5=-0.75(x-1)[/tex]
We have that the coefficient of the linear term is negative (-0.75), so, the slope is negative (the function is decreasing).
Evaluating the points, we have:
Evaluating (-1,5)
[tex]5-5=-0.75(-1-1)[/tex]
[tex]0=-3.5[/tex]
Hence, we have that since the equation is not satisfied, the line shown is not passing through the point (-1,5) meaning that the equation is not an equation of the line shown.
So, we have that the equation B is not equation of the line shown.
C.
[tex]y-3=-0.75(x-2)[/tex]
We have that the coefficient of the linear term is negative (-0.75), so, the slope is negative (the function is decreasing).
Evaluating the points, we have:
Evaluating (-1,5)
[tex]5-3=-0.75(-1-2)[/tex]
[tex]2=-0.75(-3)[/tex]
[tex]2=2.25[/tex]
Hence, we have that since the equation is not satisfied, the line shown is not passing through the point (-1,5) meaning that the equation is not an equation of the line shown.
So, we have that the equation B is not equation of the line shown.
D.
(assuming you committed a mistake writing the options and the equality sign is missing)
[tex]y-5=-0.75(x+1)[/tex]
We have that the coefficient of the linear term is negative (-0.75), so, the slope is negative (the function is decreasing).
Evaluating the points, we have:
Evaluating (-1,5)
[tex]5-5=-0.75(-1+1)[/tex]
[tex]0=-0.75(0)[/tex]
[tex]0=0[/tex]
Evaluating (3,2)
[tex]2-5=-0.75(3+1)[/tex]
[tex]-3=-0.75(4)[/tex]
[tex]-3=-3[/tex]
We have that the equation is satisfied, so, the line pass through the given points.
Hence, we have that the equation B is an equation of the line shown.
Finally, we have that the correct options are:
A) [tex]y-2=-0.75(x-3)[/tex]
and
D) [tex]y-5=-0.75(x+1)[/tex]
Have a nice day!