Question

The decomposition of N2O5 can be described by the equation.2N2O5 (soln) ---> 4NO2 (soln) + 2 (g)Given this data for the reaction at 45 degrees C in carbon tetrachloride solution, calculate the average rate for each successive time interval.t(s) [N2O5] (M)0 2.10195 1.86556 1.48825 1.25Interval: 0 s to 195 sReaction rate= _____M/s195 s to 556 sReaction rate= _____M/s556 s to 825 sReaction rate= _____M/s

Answer 1

Answer:

Rate 1 => 1.2E-3 M/s, Rate 2 => 1.05E-3 M/s, Rate 3 => 8.9E-4 M/s

Explanation:

Rate = Δ[N₂O₅]/Δtime

Rate 1 = (1.86556 - 2310195)M/(195 - 0)s = -1.2 x 10⁻³ M/s

Same for Rates 2 & 3.

Answer 2

The rate of reaction can be calculated in terms of the consumption of the reactants in the reaction.

In the given equation $\rm N_2O_5$ has been the reactant that has been used 2 moles.

The rate of the reaction has been = $\rm -\dfrac{1}{2}\;\times\;\dfrac{dN_2O_5}{dt}$

• The reaction rate for time interval 0s - 195 sec, can be given by:

Reaction rate = $\rm -\dfrac{1}{2}\;\times\;\dfrac{1.86556\;-\;2.10195}{195\;s\;-\;0\;s}$

= $\rm -\dfrac{1}{2}\;\times\;\dfrac{-0.23639}{195\;s}$

= 0.0006 M/s.

• The rate of reaction for time interval 195s - 556s, can be given by:

Reaction rate = $\rm -\dfrac{1}{2}\;\times\;\dfrac{1.48825\;-\;1.86556}{556\;s\;-\;195\;s}$

= $\rm -\dfrac{1}{2}\;\times\;\dfrac{-0.416735}{361\;s}$

= 0.0005 M/s

• The rate of reaction for time interval 556s - 825s, can be given by:

= $\rm -\dfrac{1}{2}\;\times\;\dfrac{1.25\;-\;1.48825}{825\;s\;-\;556\;s}$

= $\rm -\dfrac{1}{2}\;\times\;\dfrac{-0.23825}{269\;s}$

= 0.0004 M/s.

For more information about the rate of reaction, refer to the link:

https://brainly.com/question/8592296