Question

Please help.

Whats thr volume of a right pyramid whose base is a square with a side 6m long and whose altitude is equal to the base side?

Answer 1

V=(1/3)(area of the base)(altitude)

V=(1/3)(6²)(6)= 72 m³

Answer 2

Answer:  $72\text{ cubic meters}$

Step-by-step explanation:

Given: The base of the right pyramid is square with side = 6 m

Since, the altitude (h) is equals to the base , thus h=6m.

We know that the volume of the square pyramid is given by :_

$\text{Volume}=\frac{1}{3}a^2h$, where a is the side of the square.

Then, the volume of the given right pyramid is given by :_

$\text{Volume}=\frac{1}{3}(6)^2(6)\\\\\Rightarrow\ \text{Volume}=72\text{ cubic meters}$