Respuesta :

Answer:

2(x - 10)(x + 10)

Step-by-step explanation:

Given

2x² - 200 ← factor out 2 from each term

= 2(x² - 100) ← x² - 100 is a difference of squares and factors as

x² - 100 = x² - 10² = (x - 10)(x + 10), hence

2x² - 200 = 2(x - 10)(x + 10)

Answer:

Step-by-step explanation:

If your equation is [tex]2x^2-200[/tex] and you're to factor it, the first thing you do is set the expression equal to 0 so you can solve for x.

[tex]2x^2-200=0[/tex]

There's a couple of different ways in which to approach this.  You can factor out a 2:

[tex]2(x^2-100)=0[/tex]

and solve it from there.  The Zero Product Property says that if the equation is equal to 0, then either 2 has to equal 0 or [tex]x^2-100[/tex] has to equal 0.  We know that 2 does not equal 0, so [tex]x^2-100=0[/tex]

Add 100 to both sides in the equation:

[tex]x^2=100[/tex]

and then take the square root of both sides.  Because this is a second degree polynomial, we expect to have 2 solutions, and we do.  Don't forget that when you take the square root of a number you have to alow for both the positive and the negative of the result.  Our factored form of the given equation then is that x = 10 and x = -10.

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