Respuesta :
Answer:
2(x - 10)(x + 10)
Step-by-step explanation:
Given
2x² - 200 ← factor out 2 from each term
= 2(x² - 100) ← x² - 100 is a difference of squares and factors as
x² - 100 = x² - 10² = (x - 10)(x + 10), hence
2x² - 200 = 2(x - 10)(x + 10)
Answer:
Step-by-step explanation:
If your equation is [tex]2x^2-200[/tex] and you're to factor it, the first thing you do is set the expression equal to 0 so you can solve for x.
[tex]2x^2-200=0[/tex]
There's a couple of different ways in which to approach this. You can factor out a 2:
[tex]2(x^2-100)=0[/tex]
and solve it from there. The Zero Product Property says that if the equation is equal to 0, then either 2 has to equal 0 or [tex]x^2-100[/tex] has to equal 0. We know that 2 does not equal 0, so [tex]x^2-100=0[/tex]
Add 100 to both sides in the equation:
[tex]x^2=100[/tex]
and then take the square root of both sides. Because this is a second degree polynomial, we expect to have 2 solutions, and we do. Don't forget that when you take the square root of a number you have to alow for both the positive and the negative of the result. Our factored form of the given equation then is that x = 10 and x = -10.