Given: mTP= 70°,m∠EPT = 54° Find: Angles of △SPT

Answer:
The Angles of △SPT are
[tex]m\angle STP=35\°[/tex]
[tex]m\angle SPT=126\°[/tex]
[tex]m\angle PST=19\°[/tex]
Step-by-step explanation:
step 1
Find the measure of angle PET
we know that
The inscribed angle is half that of the arc it comprises.
[tex]m\angle PET=\frac{1}{2}(arc\ PT)[/tex]
substitute the given values
[tex]m\angle PET=\frac{1}{2}(70\°)[/tex]
[tex]m\angle PET=35\°[/tex]
step 2
Find the measure of angle PTE
we know that
The sum of internal angles of a triangle must be equal to 180 degrees
In the triangle PET
[tex]m\angle PET+m\angle EPT+m\angle PTE=180\°[/tex]
substitute the given values
[tex]35\°+54\°+m\angle PTE=180\°[/tex]
[tex]m\angle PTE=180\°-89\°=91\°[/tex]
step 3
Find the measure of angle STP
we know that
The inscribed angle is half that of the arc it comprises.
[tex]m\angle STP=\frac{1}{2}(arc\ TP)[/tex]
substitute the given values
[tex]m\angle STP=\frac{1}{2}(70\°)=35\°[/tex]
step 4
Find the measure of angle SPT
we know that
[tex]m\angle SPT+m\angle EPT=180\°[/tex] ----> by supplementary angles
[tex]m\angle SPT+54\°=180\°[/tex]
[tex]m\angle SPT=180\°-54\°=126\°[/tex]
step 5
Find the measure of angle PST
we know that
The sum of internal angles of a triangle must be equal to 180 degrees
In the triangle SPT
[tex]m\angle STP+m\angle SPT+m\angle PST=180\°[/tex]
substitute the given values
[tex]35\°+126\°+m\angle PST=180\°[/tex]
[tex]m\angle PST=180\°-161\°=19\°[/tex]