The number of milligrams of a certain medicine a veterinarian gives to a dog varies directly with the weight of the dog. If the veterinarian gives a 30-pound dog \frac{3}-{5} milligram of the medicine, which equation relates the weight, w, and the dosage, d?

Respuesta :

Answer:

[tex]d = \frac{1}{50} k[/tex]

Step-by-step explanation:

Let

w be the weight of the dog

and

d be the dosage given to the dog

As both of them are directly proportional

d ∝ w

Whenever the proportion symbol is removed from proportion, a proportionality constant is introduced.

So,

d = kw      Eqn 1

As we are given the values of d and w, putting the values

3/5 = 30k

[tex]\frac{3}{5*30} = k[/tex]

[tex]\frac{3}{150} = k[/tex]

So,

k = 1/50

Putting

K=1/50 in Eqn 1

[tex]d = \frac{1}{50} k[/tex]

So d = 1/50 * k relates dosage and weight ..

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