Answer:
[tex]d = \frac{1}{50} k[/tex]
Step-by-step explanation:
Let
w be the weight of the dog
and
d be the dosage given to the dog
As both of them are directly proportional
d ∝ w
Whenever the proportion symbol is removed from proportion, a proportionality constant is introduced.
So,
d = kw Eqn 1
As we are given the values of d and w, putting the values
3/5 = 30k
[tex]\frac{3}{5*30} = k[/tex]
[tex]\frac{3}{150} = k[/tex]
So,
k = 1/50
Putting
K=1/50 in Eqn 1
[tex]d = \frac{1}{50} k[/tex]
So d = 1/50 * k relates dosage and weight ..