Question

Which equation describes the circle having center point (4,2) and radius r= 3 in standard form?

Answer 1

ANSWER

${(x - 2)}^{2} + {(y - 4)}^{2} = 9$

EXPLANATION

The standard equation of a circle with center (h,k) and radius r is given by :

${(x - h)}^{2} + {(y - k)}^{2} = {r}^{2}$

We were given the center (4,2) and radius r=3.

We substitute the center and radius into the equation to obtain:

${(x - 2)}^{2} + {(y - 4)}^{2} = {3}^{2}$

This simplifies to:

${(x - 2)}^{2} + {(y - 4)}^{2} = 9$

Hence the equation of the circle in standard form is

${(x - 2)}^{2} + {(y - 4)}^{2} = 9$

Answer 2

Answer:

(x-4)^2+(y-2)^2=9

Step-by-step explanation:

The person above me isn't right. I just did on apex and it was correct, so.