a glass cylinder has a diameter of 7 inches and a height of 1.5 inches. Glass had a density of 2.58 grams per cubic centimeter. Find the mass of the cylinder to the nearest gram.

Respuesta :

Answer:

The mass of the cylinder is [tex]149\ g[/tex]

Step-by-step explanation:

step 1

Find the volume of the cylinder

The volume is equal to

[tex]V=\pi r^{2} h[/tex]

we have

[tex]r=7/2=3.5\ in[/tex] ----> the radius is half the diameter

[tex]h=1.5\ in[/tex]

assume

[tex]\pi=3.14[/tex]

substitute

[tex]V=(3.14)(3.5)^{2}(1.5)[/tex]

[tex]V=57.70\ in^{3}[/tex]

step 2

Find the mass

we know that

The density is equal to the mass divided by the volume

[tex]D=m/V[/tex]

Solve for the mass

[tex]m=D*V[/tex]

substitute the values

[tex]m=(2.58)*(57.70)=149\ g[/tex]

Answer:

2441 grams

Step-by-step explanation:

convert 7 and 1.5 inches into centimeters (2.54 centimeters per inch) so now you use half of 8.89 (7 * 2.54 = 2441) multiplied by 3.81

you find the area of the cylinder first by using [tex]\pi r^2*h[/tex] which should give you 945.97219

then plug it into the density formula, 2.58= mass/945.97219

that should give you mass=2440.61

and if you round it to the nearest gram, it's 2441

**THIS IS THE CORRECT ANSWER**

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