6.
What is the value of x?
24
30
40
38

You must do pythagorean theorem:
a^2 + b^2 = c^2
a and b are the legs and c is the hypotenuse
In this triangle...
a = 16
b = x
c = 34
so...
16^2 + x^2 = 34^2
256 + x ^2 = 1156
x^2 = 900
Then to isolate x square root both sides. This will get rid of the square on the x value.
This will give you...
30
x is 30
Hope this helped!
Answer: second option
Step-by-step explanation:
You need to apply the Pythagorean theorem:
[tex]a^2=b^2+c^2[/tex]
Where "a" is the hypotenuse and "b" and "c" are the legs of the right triangle.
In the figure you can observe the value the hypotenuse of the right triangle and the value of one of this leg. Then, you need to solve for the other leg from [tex]a^2=b^2+c^2[/tex]:
[tex]b^2=a^2-c^2[/tex]
[tex]b=\sqrt{a^2-c^2}[/tex]
Substituting values, you get that the value of "x" is:
[tex]b=\sqrt{(34)^2-(16)^2}[/tex]
[tex]b=30[/tex]