Answer:
0.61
Step-by-step explanation:
The average rate of change of H(s) in the closed interval [ a, b ] is
[tex]\frac{H(b)-H(a)}{b-a}[/tex]
here [ a, b ] = [ 80, 100 ]
H(b) = H(100)
= 0.003 × 100² + 0.07 × 100 - 0.027
= 30 + 7 - 0.027 = 36.973
H(a) = H(80)
= 0.003 × 80² + 0.07 × 80 - 0.027
= 19.2 + 5.6 - 0.027 = 24.773
Hence
average rate of change = [tex]\frac{36.973-24.773}{100-80}[/tex] = [tex]\frac{12.2}{20}[/tex] = 0.61
