Question

chem help 36 and 37 the word cut off on 37 is larger​

Answer 1

The solution for problem 36 is in the picture attached. I am 80% sure it’s correct.

Answer 2

• 1mol occupies 22.4L at STP

moles of Oxygen:-

• 5/22.4=0.223

Molecules of oxygen:-

• 0.223×6.022×10^23=1.343×10^23molecules

Now

Same

$\\ \rm\Rrightarrow No\:of\:moles=\dfrac{1.343(10^{23})}{6.022(10^{23})}$

$\\ \rm\Rrightarrow 0.223mol$

Volume remains same 5L

#37

• Degree of freedom of CO_2=5
• Degree of freedom of H_2=3

So velocity is more