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Answer: C. [tex]\triangle{ABC}\sim\triangle{ADB}[/tex]

D. [tex]\triangle{ABC}\sim\triangle{BDC}[/tex]

Step-by-step explanation:

Given:  [tex]\triangle{ABC}[/tex] is a right triangle in with BD is an altitude.

Now, in [tex]\triangle{ABC}[/tex] and  [tex]\triangle{ADB}[/tex], we have

[tex]\angle{A}=\angle{A}[/tex] [common]

[tex]\angle{ABC}=\angle{BDA}=90^{\circ}[/tex]

By AA- similarity postulate , we have

[tex]\triangle{ABC}\sim\triangle{ADB}[/tex]

Similarly,  in [tex]\triangle{ABC}[/tex] and  [tex]\triangle{BDC}[/tex], we have

[tex]\angle{C}=\angle{C}[/tex]  [common]

[tex]\angle{ABC}=\angle{BDC}=90^{\circ}[/tex]

By AA- similarity postulate , we have

[tex]\triangle{ABC}\sim\triangle{BDC}[/tex]

In [tex]\triangle{BDC}[/tex] and  [tex]\triangle{ADB}[/tex] only one angle is given equal . so we cannot apply any similarity postulate to show them similar.

Based on the right triangle similarity theorem, the similarity statements that are true are:

A. ΔABD ~ ΔBCD

C. ΔABC ~ ΔADB

What is the Right triangle Similarity Theorem?

The right triangle similarity theorem states that when an altitude intersects the hypotenuse of a right triangle, the two two triangles that are formed are similar to each other and also to the original triangle.

Thus, in the image given showing a right triangle with an altitude, the three triangle are all similar to each other.

Therefore, based on the right triangle similarity theorem, the similarity statements that are true are:

A. ΔABD ~ ΔBCD

C. ΔABC ~ ΔADB

Learn more about right triangle similarity theorem on:

https://brainly.com/question/10264412

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