According to the diagram below, which similarity statements are true?

Answer: C. [tex]\triangle{ABC}\sim\triangle{ADB}[/tex]
D. [tex]\triangle{ABC}\sim\triangle{BDC}[/tex]
Step-by-step explanation:
Given: [tex]\triangle{ABC}[/tex] is a right triangle in with BD is an altitude.
Now, in [tex]\triangle{ABC}[/tex] and [tex]\triangle{ADB}[/tex], we have
[tex]\angle{A}=\angle{A}[/tex] [common]
[tex]\angle{ABC}=\angle{BDA}=90^{\circ}[/tex]
By AA- similarity postulate , we have
[tex]\triangle{ABC}\sim\triangle{ADB}[/tex]
Similarly, in [tex]\triangle{ABC}[/tex] and [tex]\triangle{BDC}[/tex], we have
[tex]\angle{C}=\angle{C}[/tex] [common]
[tex]\angle{ABC}=\angle{BDC}=90^{\circ}[/tex]
By AA- similarity postulate , we have
[tex]\triangle{ABC}\sim\triangle{BDC}[/tex]
In [tex]\triangle{BDC}[/tex] and [tex]\triangle{ADB}[/tex] only one angle is given equal . so we cannot apply any similarity postulate to show them similar.
Based on the right triangle similarity theorem, the similarity statements that are true are:
A. ΔABD ~ ΔBCD
C. ΔABC ~ ΔADB
The right triangle similarity theorem states that when an altitude intersects the hypotenuse of a right triangle, the two two triangles that are formed are similar to each other and also to the original triangle.
Thus, in the image given showing a right triangle with an altitude, the three triangle are all similar to each other.
Therefore, based on the right triangle similarity theorem, the similarity statements that are true are:
A. ΔABD ~ ΔBCD
C. ΔABC ~ ΔADB
Learn more about right triangle similarity theorem on:
https://brainly.com/question/10264412