Answer:
3850 Hz
Explanation:
The auditory canal is a tube open at only one end, so we can consider it as a closed tube.
The fundamental frequency in a closed tube is given by
[tex]f_1 = \frac{v}{4L}[/tex]
where
v is the speed of sound
L is the length of the tube
Here we have
v = 348 m/s
L = 2.26 cm = 0.0226 m
So the fundamental frequency is
[tex]f=\frac{348 m/s}{4(0.0226 m)}=3,850 Hz[/tex]