Respuesta :
Answer:
[tex]\left(a+3\right)\left(a-2\right)=a^2+a-6=[/tex]
Step-by-step explanation:
Given expression is [tex]\left(a+3\right)\left(a-2\right)[/tex].
Now we need to multiply this using FOIL.
F = First [tex]=\left(a\right)\left(a\right)= a^2[/tex]
O = Outside [tex]=\left(a\right)\left(-2\right)= -2a[/tex]
I = Inside [tex]=\left(3\right)\left(a\right)= 3a[/tex]
L = Last [tex]=\left(3\right)\left(-2\right)= -6[/tex]
Hence we get :
[tex]\left(a+3\right)\left(a-2\right)=a^2-2a+3a-6=a^2+a-6=[/tex]
Answer:
[tex](a+3)(a-2)=a^2+a-6[/tex]
Step-by-step explanation:
The given expression is:
[tex](a+3)(a-2)[/tex]
Using FOIL, we multiply the;
First terms:[tex]a\times a=a^2[/tex]
Outside terms: [tex]a\times -2=-2a[/tex]
Inner terms:[tex]3\times a=3a[/tex]
Last terms:[tex]3\times -2=-6[/tex]
Putting all together we have:
[tex](a+3)(a-2)=a^2-2a+3a-6[/tex]
This simplifies to [tex](a+3)(a-2)=a^2+a-6[/tex]
