Respuesta :
Heat = Mass of water * specific heat of water * temperature rise=
15 g * 4.18 J/g K * 3K = 188J
15 g * 4.18 J/g K * 3K = 188J
The amount of heat absorbed by water is 188.28 J.
we know that, specific heat capacity is the amount of heat required to raise the temperature of 1 g of substance by 1 .0C
C = Q /W*ΔT
Q= C*W*ΔT
C= specific heat capacity
Q= amount of heat absorbed
W = weight of substance
ΔT = change in temperature
Specific heat capacity of water = 4.18 J/g.0C
Given that,
W = 15 g
ΔT = 3.0C
Q= C*W*ΔT
Q =4.184J/g. 0C*15g*3.0C
Q= 188.28 J
Thus, we can conclude that, the amount of heat absorbed by water is 188.28 J.
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