Given: OC = 1/2 OD
DC is a tangent line
Find: m∠DAC

Answer:
[tex]\implies m\angle DAC=30\degree[/tex].
Step-by-step explanation:
DC meets the circle at right angles because it is a tangent.
Triangle COD is a right triangle, with OD being the hypotenuse.
[tex]\cos m\angle COD=\frac{OC}{OD}[/tex].
But [tex]OC=\frac{1}{2}OD[/tex],
[tex]\implies \cos m\angle COD=\frac{\frac{1}{2}OD}{OD}[/tex].
[tex]\implies \cos m\angle COD=\frac{1}{2}[/tex].
[tex]\implies m\angle COD=\cos ^{-1}(\frac{1}{2})[/tex].
[tex]\implies m\angle COD=60\degree[/tex].
But [tex]m\angle DAC=\frac{1}{2} m\angle COD[/tex].
[tex]\implies m\angle DAC=\frac{1}{2}(60\degree)[/tex].
[tex]\implies m\angle DAC=30\degree[/tex].
Answer:
See below
Step-by-step explanation:
Actully, incase some people input it wrong, the answer is 30 degrees. DEGREES<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<
so input 30 degrees