Question

(3x^-2y)*(8xy^-3) --- SOLVE

Answer 1

1 Use Negative Power Rule: x−a=1xax−a=1xa
3×1x2y×8xy−33×1x2y×8xy−3
2 Use Negative Power Rule: x−a=1xax−a=1xa
3×1x2y×8x×1y33×1x2y×8x×1y3
3 Simplify
24yxx2y324yxx2y3
4 Use Quotient Rule: xaxb=xa−bxaxb=xa−b
24y1−3x1−224y1−3x1−2
5 Simplify 1−31−3 to −2−2
24y−2x1−224y−2x1−2
6 Simplify 1−21−2 to −1−1
24y−2x−124y−2x−1
7 Use Negative Power Rule: x−a=1xax−a=1xa
24×1y2x−124×1y2x−1
8 Use Negative Power Rule: x−a=1xax−a=1xa
24×1y2×1x24×1y2×1x
9 Simplify
24y2x24y2x

Answer 2

$(3x^2-2y)*( 8xy ^{-3} )$

Remove parentheses : (a) = a

$= (3x^2-2y) * 8xy ^{-3}$

$y^{-3}$

Apply  expoent rule

 $a ^{-b} = \frac{1}{a ^{b} }$

$= \frac{1}{y^3}$

$8x \frac{1}{y^3} (3x^2-2y)$

Multiply fractions:

$a* \frac{b}{c} = \frac{a*b}{c}$

$= \frac{8(3x^2-2y)}{y^3}$

hope this helps!