Question

YO DOWGS HELP ME!!!!!!!!!

Answer 1

recall that an absolute value expression is in effect a piece-wise with a ± version.

$\bf |x-1| > 2\implies \begin{cases} +(x-1)>2\implies x-1>2\\\\ ~\hfill x>3\\ \cline{1-1} -(x-1)>2\implies x-1\stackrel{\downarrow }{<}-2\\\\ ~\hfill x<-1 \end{cases}$

Check the picture below.

Answer 2

Answer:

|x - 1| > 2

Step-by-step explanation:

$x< -1\ or\ x>3\\\\\dfrac{-1+3}{2}=\dfrac{2}{2}=1\\\\x<-1\ or\ x>3\qquad\text{subtract 1 from all sides}\\\\x-1<-2\ or\ x-1>2\to|x-1|>2$