Question

Tell whether the System has one solution infinite solution many solutions or no solutions 5x-3y=10 10x+6y=20

Answer 1

ANSWER

The system has one solution.

EXPLANATION

The given system is

1st: 5x-3y=10

2nd: 10x+6y=20

Make y the subject in the first equation to get:

$y = \frac{5}{3} x + \frac{10}{3}$

Solve for y in the second equationquation to get;

$y = - \frac{5}{3} x + \frac{10}{3}$

The slope of the two equations are not the same.

The two lines will intersect at exactly one point.

.The system has one solution.

Answer 2

Answer:

One solution

Step-by-step explanation:

We are given the following system of equations and we are to tell if the system has one solution, infinite solution, many solutions or no solutions:

$5x-3y=10$ --- (1)

$10x+6y=20$ --- (2)

If we take the common out from (2), we get:

$2(5x+3y) = 20$

$5x+3y = 10$ --- (3)

So adding the two equations (1) and (3) gives 10x=20 ⇒ x=2.

Therefore, this system of equations has one solution.