Question

Which product of prime polynomials is equivalent to 36x3 – 15x2 – 6x? x(3x – 2)(4x + 1) 3x(3x – 2)(4x + 1) 3(x2 + 1)(4x – 1) 3(x2 + 1)(4x + 1)

Answer 1

Answer:

3x (3x-2)(4x+1)

Step-by-step explanation:

36x^3 – 15x^2 – 6x

factor out the "3x"

3x (12x^2-5x-2)

3x(3x - 2) (4x + 1)

= 9x^2 - 6x (4x + 1)

= 36x^3 + 9x^2 + -  24x^2 - 6x

= 36x^3 - 15x^2 - 6x

hope this helps!

Answer 2

The product of prime polynomials is equivalent to Option (A)  $3x(3x - 2)(4x + 1)$.

Concept of prime polynomial -

In mathematics, an irreducible polynomial (or prime polynomial) is approximately a non-constant polynomial that cannot be factored into the product of two non-constant polynomials. The expression can be expressed in product of prime polynomial by converting it into the factored form.

How to solve the given polynomial expression into product of prime polynomials ?

Given polynomial expression = $36x^{3} - 15x^{2} - 6x$

Solving the polynomial expression in factored form -

⇒ $3x(12x^{2} - 5x - 2)$

⇒ $3x(12x^{2} - 8x + 3x - 2)$

⇒ $3x[4x(3x - 2) + 1(3x - 2)]$

⇒ $3x(3x - 2)(4x + 1)$

Therefore the product of prime polynomial is $3x(3x - 2)(4x + 1)$

To learn more about product of prime polynomial, refer -

https://brainly.com/question/9891621

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