Question

Write x^2 + 6x -7 in the form (x+a)^2 +b where a and b are integers please

Answer 1

Answer:

$(x + 3) {}^{2} - 16$

Step-by-step explanation:

${x}^{2} + 6x - 7 = (x + 3) {}^{2} - (3) {}^{2} - 7 \\ = (x + 3) {}^{2} - 16$