Respuesta :

ANSWER

Frequency=2

Midline =3

Amplitude =5

Period =π

EXPLANATION

We have:

[tex]f(x) = 5 \cos(x) + 3[/tex]

The given function is of the form;

[tex]f(x) = a\cos(bx) + c[/tex]

where

a=|5| =5 is the amplitude

and b=2 is the frequency.

and 2π/b=2π/2=π

The range of the given function is

8≤y≤-2

The midline is

[tex] \frac{8 + - 2}{2} = \frac{6}{2} = 3[/tex]

Answer:

1. y = 3 - b. Midline

2. 2 - a. Frequency

3. 5 - c. Amplitude

4. π - d. Period

Step-by-step explanation:

We know that the standard cosine equation is in the form:

[tex] f(x) = a\cos(bx)+c [/tex]

where [tex] a [/tex] = amplitude,

[tex] b [/tex] = frequency,

[tex] c [/tex] = midline.

Therefore, for the given cosine equation:

Amplitude = 5,

Frequency = 2,

Midline = y = 3

Period = π

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