Use Euler's Formula

2) vertices: 11
Edges: 34
Faces: ?
A: 25
B: 28
C: 26
D: 24

3: Edges: 36
Faces: 22
Vertices: ?
A: 19
B: 15
C: 16
D: 17

4) Faces: 12
Vertices: 10
Edges: ?
A: 23
B: 22
C: 25
D: 20

# 5 has a picture attached with the answer choices

If you help can you maybe explain how to do one of them for me it would really help me out a lot!

Use Eulers Formula 2 vertices 11 Edges 34 Faces A 25 B 28 C 26 D 24 3 Edges 36 Faces 22 Vertices A 19 B 15 C 16 D 17 4 Faces 12 Vertices 10 Edges A 23 B 22 C 25 class=

Respuesta :

Answer:

Part 2) Option A: 25

Part 3) Option C: 16

Part 4) Option D: 20

Part 5) pentagon

Step-by-step explanation:

we know that

The Euler's formula state that, the number of vertices, minus the number of edges, plus the number of faces, is equal to two

so

[tex]V- E+ F=2[/tex]

Part 2) we have

vertices: 11

Edges: 34

Faces: ?

substitute the values in the formula and solve for F

[tex]11- 34+ F=2[/tex]

[tex]-23+ F=2[/tex]

Adds 23 both sides

[tex]F=2+23[/tex]

[tex]F=25[/tex]

Part 3) we have

Edges: 36

Faces: 22

Vertices: ?

substitute the values in the formula and solve for V

[tex]V- 36+ 22=2[/tex]

[tex]V- 14=2[/tex]

Adds 14 both sides

[tex]V=2+14[/tex]

[tex]V=16[/tex]

Part 4) we have

Faces: 12

Vertices: 10

Edges: ?

substitute the values in the formula and solve for E

[tex]10- E+ 12=2[/tex]

[tex]- E+ 22=2[/tex]

Subtract 22 both sides

[tex]- E=2-22[/tex]

[tex]- E=-20[/tex]

Multiply by -1 both sides

[tex]E=20[/tex]

Part 5) we know that

The cross section of the figure is a plane figure with five straight sides and five angles

therefore

The figure is a pentagon

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