Find the area of the trapezoid to the nearest tenth.
plz help :(
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Check the picture below.
[tex]\bf \textit{area of a trapezoid}\\\\ A=\cfrac{h(a+b)}{2}~~ \begin{cases} a,b=\stackrel{bases}{parallel~sides}\\ h=height\\ \cline{1-1} a=0.5\\ b=1.3\\ h=\frac{1.1}{\sqrt{2}} \end{cases}\implies A=\cfrac{\frac{1.1}{\sqrt{2}}(0.5+1.3)}{2} \\\\\\ A=\cfrac{~~\frac{1.1(1.8)}{\sqrt{2}}~~}{\frac{2}{1}}\implies A=\cfrac{1.98}{2\sqrt{2}}\implies A=\cfrac{0.99}{\sqrt{2}}\implies A\approx 0.7[/tex]