For this case we will show that the correct option is option C.
[tex]x ^ 2 \leq16[/tex]
We find the value of the variable "x":
We apply root to both sides of the equation to eliminate the exponent:
[tex]x \leq \pm \sqrt {16}\\x \leq \pm4[/tex]
We found the first solution with the positive value:
[tex]x \leq4[/tex]
We use the negative value to find the other solution. Since it is an inequality, the sign of the inequality changes in the negative portion of the solution.
[tex]x \geq-4[/tex]
So, the roots are:
[tex]x_ {1} \geq-4\\x_ {2} \leq + 4[/tex]
The solution is given by the values of "x" greater than or equal to -4 and less than or equal to 4
Answer:
Option C
