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When solved for x, what is the sum when the roots of the quadratic equation are added?

x^2 + 10x + 24 = 0

When solved for x what is the sum when the roots of the quadratic equation are added x2 10x 24 0 class=

Respuesta :

Answer:

A

Step-by-step explanation:

x² + 10x + 24 = 0

Here, a = 1, b = 10, c = 24.  Factoring using the AC method:

ac = 1×24 = 24

Factors of 24 that add up to 10 are +4 and +6.

Therefore:

(x + 4) (x + 6) = 0

x + 4 = 0, x + 6 = 0

x = -4, x = -6

The roots are -4 and -6.  Added together:

-4 + -6 = -10

Answer A.

Answer:

-x2-10x+24=0

Two solutions were found :

x = 2

x = -12

Step by step solution :

Step 1 :

Step 2 :

Pulling out like terms :

2.1 Pull out like factors :

-x2 - 10x + 24 = -1 • (x2 + 10x - 24)

Trying to factor by splitting the middle term

2.2 Factoring x2 + 10x - 24

The first term is, x2 its coefficient is 1 .

The middle term is, +10x its coefficient is 10 .

The last term, "the constant", is -24

Step-1 : Multiply the coefficient of the first term by the constant 1 • -24 = -24

Step-2 : Find two factors of -24 whose sum equals the coefficient of the middle term, which is 10 .

-24 + 1 = -23

-12 + 2 = -10

-8 + 3 = -5

-6 + 4 = -2

-4 + 6 = 2

-3 + 8 = 5

-2 + 12 = 10 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -2 and 12

x2 - 2x + 12x - 24

Step-4 : Add up the first 2 terms, pulling out like factors :

x • (x-2)

Add up the last 2 terms, pulling out common factors :

12 • (x-2)

Step-5 : Add up the four terms of step 4 :

(x+12) • (x-2)

Which is the desired factorization

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