Question

What are the x and y coordinates of point C which partitions the directed line segment from A to B into the ratio 3:10 round to the nearest tenth of necessary
X= (-2.6) (-2.2) (0.7) (3.4)
Y= (-5.2) (2.9) (5.2) (8.9)

Answer 1

Answer:

x=-2.6

y=5.2

Step-by-step explanation:

The endpoint of line AB are at:

A(-4,8) and B(2,-4)

The x-coordinate of the point that divides this AB in the ratio m:n=3:10 is

$x=\frac{mx_2+nx_1}{m+n}$

We substitute the given values to obtain;

$x=\frac{3(2)+10(-4)}{3+10}$

We simplify to get:

$x=\frac{6-40}{13}$

$x=\frac{-34}{13}$

$x=-2.6$

The y-coordinate of the point that divides this AB in the ratio m:n=3:10 is

$y=\frac{my_2+ny_1}{m+n}$

We substitute the given values to obtain;

$y=\frac{3(-4)+10(8)}{3+10}$

We simplify to get:

$y=\frac{-12+80}{13}$

$y=\frac{68}{13}$

$y=5.2$

Answer 2

Answer:

x= -2.6

y= 5.2

Step-by-step explanation: