Question

In pea plants, the gene for the color of the seed has two alleles. In the Punnett square shown below, the dominant allele (Y) represents yellow and the recessive allele (y) represents green.

Punnett Square showing a grid that is blank with 4 empty boxes, two columns and two rows. The female parent plant across the horizontal side, top, of the grid indicates a yellow phenotype and a genotype of Yy. The male parent plant along the vertical side of the grid indicates a yellow phenotype and a genotype of YY.

Based on the Punnett square, what percentage of offspring would have genotype YY?

0%
25%
50%
100%

Answer 1

Answer:

50%

Explanation:

.

Answer 2

Answer:

Option C

Explanation:

Given-

The genotype of female parent is "Yy"

The genotype of male parent is "YY"

The cross between the two parents is shows as below

Yy x YY

Y y

Y YY Yy

Y YY Yy

Thus, out of four offspring two have genotype "YY" and other two have genotype "Yy"

Thus, percentage of offspring that would have genotype YY is $\frac{2}{4} * 100\\= 50$%

Hence,option C is correct.