Question

Use the function below to find F(1). F(t)=2•1/2^3t

Answer 1

Answer:

Final answer is $F\left(1\right)=0.2625$.

Step-by-step explanation:

Given function is $F\left(t\right)=\frac{2.1}{2^3t}$.

Now we need to use that function $F\left(t\right)=\frac{2.1}{2^3t}$ to find the value of F(1).

F(1) means value of functino F(t) at t=1, So plug t=1 into given function.

$F\left(t\right)=\frac{2.1}{2^3t}$

$F\left(1\right)=\frac{2.1}{2^3(1)}$

$F\left(1\right)=\frac{2.1}{8(1)}$

$F\left(1\right)=\frac{2.1}{8}$

$F\left(1\right)=0.2625$

Hence final answer is $F\left(1\right)=0.2625$.

Answer 2

Answer:

The solution is $F(1) = \frac{1}{4}$

Step-by-step explanation:

Given function is $2\times \frac{1}{2^{3t}}$

We need to find the value of function $F(t) = 2\times \frac{1}{2^{3t}}$ at t = 1

Replace t with 1 in $F(t) = 2\times \frac{1}{2^{3t}}$

$F(1) = 2\times \frac{1}{2^{3(1)}}$

$F(1) = 2\times \frac{1}{2^{3}}$

$F(1) = 2\times \frac{1}{8}$

$F(1) = \frac{2}{8}$

$F(1) = \frac{1}{4}$

Therefore, the solution is $F(1) = \frac{1}{4}$