Question

PLEASE HELP!!!
A reaction is in equilibrium as shown: A + B C + D. Calculate the equilibrium constant if the final concentrations stabilize at:

A = 9.60 M
B = 10.0 M
C = 4.00 M
D = 4.00 M

Answer 1

Well...
A + B = C + D

(CD) / (AB)

(4) (4) / (9.6) (10)

16 / 96 = 0.167

Hope this helps!

Answer 2

Answer : The value of equilibrium constant is, 0.166

Solution : Given,

Concentration of A = 9.60 M

Concentration of B = 10.0 M

Concentration of C = 4.00 M

Concentration of D = 4.00 M

The equilibrium reaction will be,

$A+B\rightleftharpoons C+D$

The expression for equilibrium constant is,

$K_c=\frac{[C][D]}{[A][B]}$

Now put all the given values in this expression, we get the values of equilibrium constant.

$K_c=\frac{(4M)\times (4M)}{(9.60M)\times (10M)}=0.166$

Therefore, the value of equilibrium constant is, 0.166