Respuesta :
F=ma
a=F/m
F=+250N + (-130N)=120N LEFT
('m summing my forces because they are moving about the same axis, and the negative/positive accounts for the arbitrary directions I assign)
m=32kg
F=120N/32kg=3.75m/s^2 to the LEFT
3.75m/s^2 to the LEFT
a=F/m
F=+250N + (-130N)=120N LEFT
('m summing my forces because they are moving about the same axis, and the negative/positive accounts for the arbitrary directions I assign)
m=32kg
F=120N/32kg=3.75m/s^2 to the LEFT
3.75m/s^2 to the LEFT
The acceleration of the couch is required.
The acceleration of the couch is [tex]3.75\ \text{m/s}^2[/tex] towards the left.
Let the direction towards the right be positive and left be negative.
[tex]F_1=-250\ \text{N}[/tex]
[tex]F_2=130\ \text{N}[/tex]
Net force
[tex]F=F_1+F_2\\\Rightarrow F=-250+130\\\Rightarrow F=-120\ \text{N}[/tex]
m = Mass of couch = 32 kg
Force is given by
[tex]F=ma\\\Rightarrow a=\dfrac{F}{m}\\\Rightarrow a=\dfrac{-120}{32}\\\Rightarrow a=-3.75\ \text{m/s}^2[/tex]
The acceleration of the couch is [tex]3.75\ \text{m/s}^2[/tex] towards the left.
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