Question

what is the mass of 3.0 x 10^23 atoms of neon

Answer 1

Answer: The mass of neon for the given number of atoms will be 9.8 g.

Explanation:

We are given:

Number of neon atoms = $3.0\times 10^{23}$

According to the mole concept:

$6.022\times 10^{23}$ number of atoms. are occupied in 1 mole of a substance.

So, $3.0\times 10^{23}$ will be occupied in = $\frac{1}{6.022\times 10^{23}}\times 3.0\times 10^{23}=0.49moles$

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Moles of Neon = 0.49 moles

Molar mass of neon = 20 g/mol

Putting values in above equation, we get:

$0.49mol=\frac{\text{Mass of neon}}{20g/mol}\\\\\text{Mass of neon}=9.8g$

Hence, the mass of neon for the given number of atoms will be 0.49g.

Answer 2

The mass of 3.0 x 10^23 atoms of neon would be 10.09 g

According to Avogadro;

1 mole of neon would have 6.022 x 10^23 atoms

3.0 x 10^23 atoms of neon would have:

            3.0 x 10^23/6.022 x 10^23

                                         = 0.5 moles

mass of 0.5 moles neon = mole x molar mass

                                            = 0.5 x 20.18

                                             = 10.09 g

More on Avogadro number can be found here: https://brainly.com/question/1445383?referrer=searchResults