Respuesta :
Let us assume the number of
shares that Rob has of Dowc Beverages Co. = x
Then
Number of shares of Agram imports held by Rob = x + 86
So
The equation can be written as
6.52x + 5.15(x + 86) = 4585.15
6.52x + 5.15x + 442.90 = 4585.15
11.67x = 4585.15 - 442.90
11.67x = 4142.25
x = 4142.25/11.67
= 354.95
= 355
Then
Number of Agram imports shares that Rob owns = x + 86
= 355 + 86
= 441
shares that Rob has of Dowc Beverages Co. = x
Then
Number of shares of Agram imports held by Rob = x + 86
So
The equation can be written as
6.52x + 5.15(x + 86) = 4585.15
6.52x + 5.15x + 442.90 = 4585.15
11.67x = 4585.15 - 442.90
11.67x = 4142.25
x = 4142.25/11.67
= 354.95
= 355
Then
Number of Agram imports shares that Rob owns = x + 86
= 355 + 86
= 441
Answer:
Number of shares owned by Rob in Agram Imports = 441
Explanation:
Let,
the number of shares owned in Agram = A
and
the number of shares owned in Dowc Beverage Co. = D
Where he owns 86 more shares of Agram Imports than he does of Dowc Beverage Co. then,
A = D + 86
when D is made the subject of the equation,
D = A - 86
Also, if Dowc Beverage Co. pays a dividend of $6.52 per share
Total payment from Dowc = $6.52D
Where Agram Imports pays a dividend of $5.15 per share,
Total payment from Agram Imports = $5.15A
Therefore, total payments received by Rob from both companies
= 6.52D + 5.15A
If Rob receives $4,585.15 in dividends annually then,
6.52D + 5.15A = 4,585.15
Recall that D = A - 86
substituting into the equation above'
6.52(A - 86) + 5.15 = 4585.15
6.52A - 560.72 + 5.15A = 4585.15
6.52A + 5.15A -560.72 = 4585.15
11.67A - 560.72 = 4585.15
Collecting like terms
11.67A = 4585.15 + 560.72
11.67A = 5145.87
Divide both sides by 11.67
[tex]\frac{11.67A}{11.67} = \frac{5145.87}{11.67}\\A = 440.9486\\A[/tex]
A ≈ 441 Shares
As such, Number of shares owned by Rob in Agram Imports is 441