The measure of the angles in order are: 40, 20, 120 degrees
Not exactly sure what the question was but I hope that answers it
Working out:
Let the measure of the second angle equal α
The first angle is double the second angle ie. 2α
The third angle is 100 more than the second angle ie. α+100
We now have three angles: 2α, α, α+100
The angle sum of a triangle is always 180°
∴2α + α + α+100 = 180 (group like terms)
4α + 100 = 180 (-100)
4α = 80 (÷4)
α = 20