Question

What molarity should the stock solution be if you ant to dilute 25.0 mL to 2.00 L and have the final concentration be 0.103M? a. 4.12M, b. 8.24 M c. 0.243 M, d. 0.206M?

Answer 1

A common dilution relationship is (M1V1)=(M2V2)
(0.103M x 2.00L) = (M2 x 0.025L)
M2= (0.103M x 2.00L)/0.025L
M2= 8.24M