Answer:
5.8 L.
Explanation:
where, P is the pressure of the gas in atm.
V is the volume of the gas in L.
n is the no. of moles of the gas in mol.
R is the general gas constant,
T is the temperature of the gas in K.
V₁T₂ = V₂T₁
V₁ = 3.8 L, T₁ = - 45.0°C + 273 = 228.0 K.
V₂ = ??? L, T₂ = 75.0°C + 273 = 348.0 K.
∴ V₂ = V₁T₂/T₁ = (3.8 L)(348.0 K)/(228.0 K) = 5.8 L.