Question

How many moles of ZnCl2 will be produced from 23.0g of Zn, assuming CuCl2 is available in excess?

Answer 1

Answer:

= 0.408 moles

Explanation:

The equation for the reaction is;

Zn + CuCl2 → ZnCl2 + Cu

Given 23.0 g of zince

Moles of Zn = 23.0/65.38 g/mol

                   = 0.408 moles

From the equation;

1 mole of Zn produces 1 mole of ZnCl2

Therefore; the number of moles of ZnCl will also be;

  = 0.408 moles × 1

  = 0.408 moles