Question

A geometric sequence {an} is defined by the function

f(1) = a1 = 6 and f(n) = an = (1.2)*f(n - 1) for n ≥ 2.

Find f(38).
A)273.6
B)326.26
C)5103.3735
D)6124.0482

Answer 1

ANSWER

C)5103.3735

EXPLANATION

The recursive definition of the given sequence is;

$f(1) = a_1 = 6$

and

$f(n) = a_n = (1.2) \times f(n - 1)$

The explicit definition is

$f(n) = a_n =6 (1.2)^{n - 1}$

We substitute n=38 to obtain:

$f(38) = a_ {38}= 6(1.2)^{37}$

$f(38) = 5103.3735$

The correct choice is C.

Answer 2

Answer:

C

Step-by-step explanation:

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