Respuesta :
Answer:
B
Explanation:
This option is exactly the same as the example. Thus it would require the same amount of heat.
Answer:
B) A 3-kg mass experiences a temperature rise of 50°C.
Explanation:
As we know that the rise in temperature for 3 kg object is 50 degree C then the heat added is given as 1000 J
so here we can say that formula of heat is
[tex]Q = ms\Delta T[/tex]
here we will have
[tex]m = mass[/tex]
s = specific heat capacity
[tex]\Delta T [/tex] = temperature rise
so here if we make all three parameters same to make this heat energy same
so correct answer will be
B) A 3-kg mass experiences a temperature rise of 50°C.