Question

A cone shaped block that has a slant height of 6 inches and has a radius of 4 inches . How many square inches of paper would it take the cover the surface?

Answer 1

Answer:

$T.S.A=40\pi in^2$

Step-by-step explanation:

The total surface area of the cone is

$\pi r^2+\pi rl$

The radius of the cone is 4 inches.

The slant height of the cone is l=6 inches.

We substitute these values into the formula to obtain;

$T.S.A=\pi \times (4)^2+\pi \times 4\times6$

$T.S.A=16\pi+24\pi$

$T.S.A=40\pi in^2$

Or

$T.S.A=125.7in^2$  to the nearest tenth.