Question

A red die is tossed and then a green die is tossed. What is the probability that the red die shows an even number or the green die shows an even number?

Answer 1

Using it's concept, it is found that there is a $\frac{3}{4}$ probability that the red die shows an even number or the green die shows an even number.

What is a probability?

A probability is given by the number of desired outcomes divided by the number of total outcomes.

A die has six sides, of which three are even and three are odd, hence:

• P(A) = 3/6 = 1/2.

• P(B) = 3/6 = 1.2.

• P(A and B) = P(A)*P(B) = 1/4.

The "or probability" is given by:

$P(A \cup B) = P(A) + P(B) - P(A \cap B)$

Hence:

$P(A \cup B) = \frac{1}{2} + \frac{1}{2} - \frac{1}{4} = \frac{3}{4}$

More can be learned about probabilities at https://brainly.com/question/14398287

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