Respuesta :
[tex]\bf \qquad \qquad \qquad \textit{discriminant of a quadratic} \\\\\\ y=\stackrel{\stackrel{a}{\downarrow }}{a}x^2\stackrel{\stackrel{b}{\downarrow }}{+b}x\stackrel{\stackrel{c}{\downarrow }}{+c} ~~~~~~~~ \stackrel{discriminant}{b^2-4ac}= \begin{cases} 0&\textit{one solution}\\ positive&\textit{two solutions}\\ \stackrel{-16}{negative}&\textit{no solution}~~\checkmark \end{cases}[/tex]
Answer:
A quadratic equation of the form 0 = ax² + bx + c with a discriminant value of –16 has no real solution
Step-by-step explanation:
A quadratic equation ax²+bx+c=0 with discriminant D=b²-4ac has
2 unequal real solutions if D is positive i.e. D>0
2 equal real roots if D=0
no real root if D is negative i.e. D<0
Here, we are given value of D= -16 which is less than zero
Hence, a quadratic equation of the form 0 = ax² + bx + c with a discriminant value of –16 has no real solution
