Question

what is the solution?

Answer 1

Answer:

$x_{12} = 4 \pm \sqrt{6}$

Step-by-step explanation:

3(x-4)^2 = 18

We divide everything by 3;

(x-4)^2 = 6

Take the square root on both sides:

$x-4 = \pm \sqrt{6}\\x_{12} = 4 \pm \sqrt{6}$