answer:
1.8E-15C/1.6E-19=11,250
Explanation:
The biochemistry that takes place inside cells depends on various elements, such as sodium, potassium, and calcium, that are dissolved in water as ions. These ions enter cells through narrow pores in the cell membrane known as ion channels. Each ion channel, which is formed from a specialized protein molecule, is selective for one type of ion. Measurements with microelectrodes have shown that a 0.30-nm-diameter potassium ion ({\rm{{\rm K}}}^{\rm{ + }} ) channel carries a current of 1.8 {\rm pA}.
The number of potassium ions that will pass through the ion channel is 11250.
Potassium ions, possibly the most often constituted electrolyte.
Calculating the number of potassium ions that passes through the ion channel
Given that the channel opens for 1.0 ms
Step1: determine the value of charge ( Q )
[tex]Q = I \times \Delta t = ( 1.8 \times 10^-^1^0 A )\times (1.0 \times 10^1^3 s ) = 1.8 \times 10^-^1^5 C[/tex]
where ; I = 1.8 × 10⁻¹² A
[tex]\Delta t = 1.0 \times 10^-^3 s[/tex]
Step2: determine number of K⁺ ions passing through
[tex]NK^+ = Q \times e = ( 1.8 \times 10^-^1^5 C )\times ( 1.60 \times 10^-^1^9 C) = 11250[/tex]
Thus, the potassium ions pass through the channel is 11250.
Learn more about potassium ions
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