Question

How many moles of KCIO3 must completely react to produce 6 moles of O2?

Answer 1

Hello!

The answer is:

4 moles of $KClO_{3}$ are required to produce 6 moles of  $O_{2}$

Why?

To solve stoichiometric problems, we need to write the balanced equation of the compound that we are working with.

Potassium chlorate decomposition is given by the following equation:

$2KClO_{3}->3KCl+3O_{2}$

Now, from the equation we know that 3 moles of $O_{2}$ gives 2 moles of $2KClO_{3}$, we can calculate how many moles of the same compound react to produce 6 moles of $O_{2}$ the following equation:

$\frac{No.molKClO_{3}}{6molO_{2}}=\frac{2molKClO_{3}}{3molO_{2}}\\\\No.molKClO_{3}=6molO_{2}*\frac{2molKClO_{3}}{3molO_{2}}\\\\No.molKClO_{3}=4molKClO_{3}$

Hence, we have that 4 moles of $KClO_{3}$ are required to produce 6 moles of  $O_{2}$

Have a nice day!