Answer:
The root of [tex]\sqrt{2y-5} +8 = 4[/tex] is 10.5.
Step-by-step explanation:
Given that,
[tex]\sqrt{2y-5} +8 = 4[/tex]
As we have a square root term along with a single term on left side. We will move the single term on right side.
[tex]\sqrt{2y-5} = 4-8[/tex]
[tex]\sqrt{2y-5} = -4[/tex]
Taking the square on both sides, we get
[tex](\sqrt{2y-5})^2 = (-4)^2[/tex]
Square will cancel the impact of square root, therefore:
[tex]({2y-5}) = 16[/tex]
[tex]2y = 16+5[/tex]
[tex]2y = 21[/tex]
[tex]y = \frac{21}{2}[/tex]
[tex]y = 10.5[/tex]
Therefore, the root of [tex]\sqrt{2y-5} +8 = 4[/tex] is 10.5.
