Question

A conical container can hold 120π cubic centimeters of water. The diameter of the base of the container is 12 centimeters.

The height of the container is___ centimeters. If its diameter and height were both doubled, the container's capacity would be_____ times its original capacity.

Answer 1

cone volume=(1/3)hpir^2
d/2=r
d=12
d/2=12/2=6=r

V=120pi
120pi=(1/3)hpi6^2
120pi=(1/3)hpi36
120pi=12hpi
divide both sides by pi
120=12h
divide 12
10=h cm


if height and diameter is doubled aka height and radius are doubled

V=(1/3)(2h)pi(2r^2)
we want to see how it compares to V=(1/3)hpir^2

V=(1/3)(2h)pi(2r^2)
V=2(1/3)(h)pi4r^2
V=8((1/3)hpir^2)
the volume is increased by 8 times


blanks are
10
8

Answer 2

Answer:

10

8

Step-by-step explanation: