Question

For the following list of​ data, calculate ​(a) the​ mean, ​(b) the​ median, and ​(c) the mode or modes​ (if any).
133, 135 , 147, 131, 147, 136
a) The mean is
_______​(Round to the nearest tenth as​ needed.)
​(b) The median is
__________

C.
The​ mode(s) is/are
__________ ​(Use a comma to separate answers as​ needed.)
B.
There is no mode.

Answer 1

Answer

a) The mean is 138.2,

b) The median is 135.5,

c) The mode is 147

step-by-step explanation

a) For the data 133, 135, 147, 131, 147, 136

The mean

$= \frac{133 +135 + 147 + 131 + 147 + 136 }{6} = 138.1667$

Hence the mean is 138.2 to the nearest tenth.

b) By definition, the median of a set of numbers is the number that appears at the middle when the set of numbers are arranged in descending or ascending order.

when it happens that two numbers appear at the middle, the median is calculated by finding the mean of these two numbers (i.e add those two numbers and divide by 2)

So, for the median , we first arrange the numbers in ascending order to get:

131, 133, 135, 136, 147, 147

In this this case the 135 and 136 happened to appear at the middle

Hence median

$= \frac{135 + 136}{2} = \frac{271}{2} = 135.5$

c) The mode of a set of numbers can be defined as the number that appears most.

From the look at the given numbers, 147 occurs most.

Hence the mode is 147

Answer 2

Answer:

a) mean = 138.1

b). median = 135.5

c) mode = 147

Step-by-step explanation:

The given data set

133, 135 , 147, 131, 147, 136

Ascending order

131, 133, 135, 136, 146, 147

a). To find the mean

Mean =  (131 + 133 + 135 + 136 + 146 + 147)/6 = 138.1

b) . To find the median

The central data -  135 and 136

median = (135 + 136)/2 = 135.5

c). To find the Mode

Mode = most recurring data

Here mode = 147