Answer:
[tex]\large\boxed{A.\ \dfrac{x+2}{x+5}}[/tex]
Step-by-step explanation:
[tex]x^2+3x+2=x^2+x+2x+2=x(x+1)+2(x+1)=(x+1)(x+2)\\\\x^2+6x+5=x^2+x+5x+5=x(x+1)+5(x+1)=(x+1)(x+5)\\\\\dfrac{x^2+3x+2}{x^2+6x+5}=\dfrac{(x+1)(x+2)}{(x+1)(x+5)}\qquad\text{cancel}\ (x+1)\\\\=\dfrac{x+2}{x+5}[/tex]
